Joseph Michael Pesch
VP Programming

SQL Server Split Function

by 12. August 2008 18:39

CREATE FUNCTION dbo.fnSplit(
    @sInputList VARCHAR(8000) -- List of delimited items
  , @sDelimiter VARCHAR(8000) = ',' -- delimiter that separates items
) RETURNS @List TABLE (recid int identity(1,1), item VARCHAR(8000))
BEGIN
-- Adapted from: http://searchvb.techtarget.com/tip/0,289483,sid8_gci932171,00.html
-- Added recid (identity column)
-- Tests
/*
  select * from fnSplit('12345', ',')
  select * from fnSplit('1,22,333,444,,5555,666', ',')
  select * from fnSplit('1##22#333##444','##')  --note second item has embedded #
  select * from fnSplit('1 22 333 444  5555 666', ' ')
*/
DECLARE @sItem VARCHAR(8000)
WHILE CHARINDEX(@sDelimiter,@sInputList,0) <> 0
 BEGIN
 SELECT
  @sItem=RTRIM(LTRIM(SUBSTRING(@sInputList,1,CHARINDEX(@sDelimiter,@sInputList,0)-1))),
  @sInputList=RTRIM(LTRIM(SUBSTRING(@sInputList,CHARINDEX(@sDelimiter,@sInputList,0)+LEN(@sDelimiter),LEN(@sInputList))))
 
 IF LEN(@sItem) > 0
  INSERT INTO @List SELECT @sItem
 END
IF LEN(@sInputList) > 0
 INSERT INTO @List SELECT @sInputList -- Put the last item in
RETURN
END
GO


Sample Usage via a Cursor:


declare
@recid int
, @item varchar(8000)
, @SampleData varchar(50)
set @SampleData = 'Item1,Item2,Item3,Item4,Item5'
declare split cursor for select * from dbo.fnSplit(@SampleData, ',')
open split
while 1=1 begin
fetch next from split into @recid, @item
if @@fetch_status <> 0 break
-- Do something here...
select @recid, @item
end
close split
deallocate split

Tags:

SQL Server

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